大菠萝

Project Euler 第6题

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

哈哈，这个题目最最简单咯，一句话Python搞定。老外的自然数好像不包括0，我的理解，前100个自然数应该为[0,99]嘛。。

sum(range(101))**2-sum(i*i for i in range(101))

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